Given the parent compound, draw the mass spectrum fragment that is observed at m/z 77. Include any hydrogen atoms and the charge. Its 6 carbon ring with 3 double bonds and a Cl coming off the of it.
Given that CaCl2 = 2.46 m
Therefore 2.46 mole of CaCl2 present in 1.00 g of solution
Mass of 2.46 mole CaCl2= number of mole * molar mass
= 2.46 mole * 110.98 g/mol
= 273.01 g
Mass of water or solvent = mass of solution – mass of solute
= 1000 g -273.01 g
= 726.99 g
Mole of water = amount in g / molar mass
= 726.99 g/18.02 g/ mole
= 40.34 moles
Mole fraction of CaCl2 = number of mole of CaCl2 / total moles
= 2.46 /2.46+40.34
= 2.46/42.8
= 0.057
The sensitivity of electronic balance is 0.3 mg
Converting 0.3 mg to g:
g
So, the mass of a substance weighed on the balance can be measured accurately up to four decimal places.
Given the mass of sample is 1.2300 g. The number of significant figures in the measurement will be 5 because the balance can measure the mass of a sample accurately up to four decimal points, all the digits in the measurement will be significant.
Answer:
a fundamental universal constant, the speed at which light and all forms of electromagnetic radiation travel in a vacuum, standardized ...
Explanation:
299 792 458 m / s
Answer:
the answer is 0 amu I hope it helps