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zubka84 [21]
3 years ago
14

PLEASE NEED HELP QUICK DEADLINE SOON

Chemistry
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

D. Protons ; neutrons.

Explanation:

For a given element the number of protons is fixed, but the number of neutrons differ because the element usually consist of a number of isotopes.

For example Carbon has isotopes which contain 12, 13 and 14 neutrons.

So that is why you average the number of neutrons to find the approximate atomic mass..

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What is the density of a substance that has a volume of 14 millimeters and a mass of 13.2 grams.
Contact [7]

Answer:

<h2>0.94 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{13.2}{14}  \\  = 0.94285...

We have the final answer as

<h3>0.94 g/mL</h3>

Hope this helps you

6 0
2 years ago
What greek letter are used in the precise definition of a limit?
Ivan
Epsilon-delta would be the green letter that is used in the precision definition of a limit. (ε, δ).
5 0
3 years ago
An alkene with the molecular formula C8H16 undergoes ozonolysis to yield a mixture of (CH3)2C=O and (CH3)3CCHO. The alkene is:
aalyn [17]

Answer:

2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

Explanation:

In ozonolysis (hydrolysis step involve a reducing agent such as Zn, Me_{2}S etc.), a pi bond is broken to form ketone/aldehyde.

Ketone is formed from di-substituted side of double bond and aldehyde is formed from mono-substituted side of double bond.

Ozoznolysis involves two consecutive steps : (1) formation of ozonide, (2) hydrolysis of ozonide.

Hydrolysis can be done with/without using reducing agent. Carboxylic acid/carbon dioxide/ketone is produced when hydrolysis is done without using reducing agent.

Here, 2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

Reaction steps are shown below.

8 0
3 years ago
Please help me!!!!
miv72 [106K]

Answer:

0.8g/ml

Explanation:

d=m/v

d=20/25

d=0.8

7 0
3 years ago
The chemical equation of rusting of iron is given
artcher [175]

Answer:

{ \tt{(a). { \bf{reactants : { \tt{iron \:  and \: oxygen}}}}}} \\ { \bf{products :  { \tt{iron(iii)oxide}}}} \\  \\ { \tt{(b).}} \: { \bf{1.204 \times  {10}^{24}  \: atoms}} \\ { \tt{(c).}} \: { \tt{4Fe +3 O _{2}  → 2Fe _{2}O _{3}}} \\  \\ { \underline{ \blue{ \tt{becker \: jnr}}}}

6 0
2 years ago
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