The square of a prime number is not prime.
a) let x ∈ R, If x ∈ {prime numbers}, then 
∉{prime numbers}
there says that if x is a real and x is in the set of the prime numbers, then the square of x isn't in the set of prime numbers.
b) Prove or disprove the statement.
ok, if x is a prime number, then x only can be divided by himself. Now is easy to see that = x*x can be divided by himself and x, then x*x is not a prime number, because can be divided by another number different than himself
Answer:
A, C, and D.
Step-by-step explanation:
<XYZ appears in the diagram as the vertex angle Y, has two sides, YW and YX that intersect at point Y to form <XYZ.
Thus, <XYZ, line segments YW and YX all appear in the diagram given.
<YXZ does not appear because there's no vertex angle labelled X.
Answer:
333 meters per second
Step-by-step explanation:
Answer:
The domain is all real numbers except x=3
Step-by-step explanation:
Assuming you mean
f(x) = 1/(x-3)
The domain is all numbers that x can take
This function is define except when the denominator goes to zero
x-3 cannot be zero
x cannot be 3
The domain is all real numbers except x=3
