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vesna_86 [32]
3 years ago
14

Regroup to express the number in a different way.

Mathematics
1 answer:
MrRissso [65]3 years ago
3 0

Answer:

add 1 hundred because you put a 1 instead of a 2

but the answer is 5 tens

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If you help me I’ll love you forever <3
eimsori [14]

Answer:

translation

Step-by-step explanation:

because a reflection across the x-axis is not right, and neither is across the y-axis. The triangle was also not rotated 90 degrees. It was translated 8 units to the right and 4 units up.

5 0
3 years ago
1.5y - 15 + 1.8y = -10<br> (for my algebra class)
vekshin1

Answer:

y=1.51

Step-by-step explanation:

6 0
3 years ago
An angle's measure is equal to 24 less than its complement. Find the angle's measure.
Monica [59]
A complementary angle is an angle that has measurements that add up with another angle to equal 90 degrees. To find the measure of the angle you would subtract 90 degrees from the measure of the given angle. So you would subtract 90 from 24 to get 66. So the measure of the angle would be 66 degrees. Thank you

If you don't mind please give brainliest.
Have a blessed day
4 0
3 years ago
If two lines have the same slope, they are
maw [93]

Answer:

Reflection

Step-by-step explanation:

they are reflection because they have the SAME slope

8 0
3 years ago
In a triangle ABC, AD is drawn perpendicular to BC. <br> Prove that AB2 - BD2 = AC2 - CD2.
Finger [1]

Answer:

Given: In triangle ABC , AD is drawn perpendicular to BC.

Since AD is drawn perpendicular to BC, it creates two right triangles: ADB and ADC.

Prove that: AB^2-BD^2 = AC^2-CD^2

Pythagoras triangle for right angle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

In a right angle triangle ADB;

AD^2+BD^2 = AB^2                 [By Pythagoras theorem]

or

AD^2= AB^2-BD^2                      .......[1]

Now, in right angle triangle ADC;

AD^2+CD^2 = AC^2                [By Pythagoras theorem]

or we can write this as;

AD^2= AC^2-CD^2                    ......[2]

Substituting the equation [1] in [2] we get;

AB^2-BD^2 =AC^2-CD^2            hence proved!

5 0
3 years ago
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