F(x)=3x^2-5 when x=-11
f(-11)=3(-11)^2-5
f(-11)=-33^2-5
f(-11)=1089-5
f(-11)= 1084
Hope this could help!
Answer:
c = 2
Step-by-step explanation:
Since 16 is over the variable c, first multiply both sides by c so the variable is not in the denominator of the fraction.
16/c(c) = 8(c)
16 = 8c Next, divide both sides by 8 to solve for c.
c = 2
For this case we have the following variable:
p: cost of the item that Arthur wants to buy before tax
The expression for the 6% tax is given by:
Or equivalently:
Therefore, two different expressions for the total cost are:
Expression 1:
Expression 2:
To prove that they are equal, suppose that the item costs $ 100:
Expression 1:
Expression 2:
Since the cost is the same, then the expressions are the same.
Answer:
Two different expressions that model the problem are:
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1
Starting with the left: Note that cos²θ + </span><span>sin²θ = 1.
In the same way: </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore cos²3θ = 1 - <span>sin²3θ
</span> From the top: (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ
= 2/<span>sin² 3θ - 1; But 1/</span><span>sinθ = csc</span><span>θ, Similarly </span>1/sin3θ = csc3θ
= 2 *(1/sin<span>3θ)² - 1</span>
= 2csc²3θ - 1. Therefore LHS = RHS. QED.
The answer will be Apples
