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Alecsey [184]
3 years ago
15

When discussing CV joints, Technician A says that they are called constant-velocity

Computers and Technology
1 answer:
Alja [10]3 years ago
8 0

A only is correct.

Constant-velocity joints are able to transfer torque with zero angular velocity variation and near-zero vibration to the drive wheels at a constant rotational speed, while still accommodating the up-and-down movement of the suspension. In most cases, they are used in front wheel drive vehicles.

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Jason, Samantha, Ravi, Sheila, and Ankit are preparing for an upcoming marathon. Each day of the week, they run a certain number
kolbaska11 [484]

Answer:

C++ program explained below for the problem

Explanation:

// UpComingMarathon.cpp : Defines the entry point for the console application.

//header files

#include "stdafx.h" //optional

#include <iostream>

#include <cstring>

#include <fstream>

#include <iomanip>

using namespace std;

//declare the gobal array of type double

double average[5];

//declare the function prototypes

void getData(ifstream& inf, string n[], double runData[][8], int count);

void calculateAverage(double runData[][8], int count);

void print(string n[], double runData[][8], int count);

int main()

{

   string names[5];

   double runningData[5][8];

   ifstream inputfile("input.txt");

   if(inputfile)

   {

        //call the method getData

        getData(inputfile, names, runningData, 5);

   }

   else

   {

        //error message

        cout<<"Sorry! Unable to open the file."<<endl;

        system("pause");

        return 0;

   }

   //close the file

   inputfile.close();

   //call the method calculateAverage to compute the

   //average miliage of each runner

   calculateAverage(runningData, 5);

   //call display the names and their weekly run rate and their averages

   print(names, runningData, 5);

   system("pause");

   return 0;

}

//definition of method getData that reads the data from the file and

//stores the names into array n and run data into runData array

//simultaneously.

void getData(ifstream& inf, string n[], double runData[][8], int count)

{  

   while(!inf.eof())

   {

        for(int i=0;i<count; i++)

        {

            inf>>n[i];

            for(int j=0;j<7;j++)

            {

                inf>>runData[i][j];

            }

        }

   }

}

//definition of method calculateAverage that comptes the total first

//then stores the value of average into the average array

void calculateAverage(double runData[][8], int count)

{

   double total;

   for(int i=0;i<count;i++)

   {

        total=0;

        for(int j=0;j<7;j++)

        {

            total+=runData[i][j];

        }        

        average[i]=total/7;      

   }

}

//definition of method print that prints the output

//in a tabular format

void print(string n[], double runData[][8], int count)

{

   cout<<setfill('=')<<setw(80)<<"=";

   cout<<setfill(' ');

   cout<<endl;

   cout<<"Name"<<setw(6)<<"";

   for(int i=0;i<7;i++)

        cout<<setw(7)<<"Day "<<(i+1);

   cout<<setw(12)<<"Average"<<endl;

   cout<<setfill('=')<<setw(80)<<"=";

   cout<<setfill(' ')<<endl;

   for(int i=0;i<count;i++)

   {

        cout<<n[i]<<setw(8)<<fixed<<"";

        for(int j=0;j<7; j++)

        {

            cout<<setprecision(2)<<fixed<<runData[i][j]<<setw(3)<<"";

        }

        cout<<setw(8)<<average[i];

        cout<<endl;

   }

   cout<<setfill('=')<<setw(80)<<"=";

   cout<<endl;

}

5 0
3 years ago
Design a class named largeIntegers such that an object of this class can store an integer of any number of digits. Add operation
SpyIntel [72]

Answer:

Here the code is given as follows,

Explanation:

Code:

import java.util.Scanner;

//created class named largeintegers

class largeintegers{

   //class can hold a long number

   long number;

   //constructor to set number

  largeintegers(long number){

      this.number=number;

  }

  //getNumber method to get number

  long getNumber(){

      return number;

  }

  //below are some basic operations

  long addition(long num1,long num2){

       return num1+num2;

   }

   long subtract(long num1,long num2){

       return num1-num2;

   }

   long multiply(long num1,long num2){

       return num1*num2;

   }

   boolean compare(long num1,long num2)

   {

       return num1>num2;

   }

  public static void main(String[] args) {

      //declared to long numbers

      long number1,number2;

      //scanner class to take user input

      Scanner sc= new Scanner(System.in);

      //taking input numbers

      System.out.println("Enter a Number ");

      number1=sc.nextLong();

      System.out.println("Enter 2nd Number :");

      number2=sc.nextLong();

      //created two objects

      largeintegers object=new largeintegers(number1);

      largeintegers object2=new largeintegers(number2);

      //displaying two numbers

      System.out.println("Entered Numbers ");

      System.out.println(object.getNumber());

      System.out.println(object2.getNumber());

      //calling basic methods using created objects

      System.out.println("Some Operations on Given two Numbers ");

      System.out.println("Addition:"+object.addition(object.getNumber(), object2.getNumber()));

      System.out.println("Subtraction:"+object.subtract(object.getNumber(), object2.getNumber()));

      System.out.println("Multiplication:"+object.multiply(object.getNumber(), object2.getNumber()));

      System.out.println("Comparison:");

      if(object.compare(object.getNumber(), object2.getNumber())==true)

      {

          System.out.println("First Number is Greater than Second Number ");

      }

      else

      {

          System.out.println("Second Number is Greater than First Number ");

      }

      sc.close();

  }

}

Output:-

6 0
3 years ago
Roy is preparing for his test in English. He creates lots of memory tools and studies using a circuit-learning schedule that he
kozerog [31]
He should get an good night sleep the day before the test, eat a filling breakfast, get to school on time, sit in his and relax. to take a test as much as you prepare for it you mustalso be calm; being frazzled will make it hard to concentrate. some streaches will release any stress and boost confidence. also letting some blood get to your brain will help you think better. to pass a test you must study, stable, relaxed, and alert.
8 0
3 years ago
Create a structure representing a student. The member variables should include student name, student ID, and four test grades fo
Neporo4naja [7]

Answer:

Output:

Name: Brainly

ID:0001

Write the 4 tests grades of the student separated by space :10 9 8 10

Brainly

0001

10 9 8 10

Average :9.66667

'1' to continue '0' to exit :

Explanation:

#include<iostream>

#include<string>

using namespace std;

//variables declaration

struct Student {

  string id; //string declaration ID

  string name; // string declaration name

  int grades[4]; //array of 4 because it is 4 grades

};

//definition of the function get information

void inputData(Student &s){

 

   

   cout << "Name:" ;

   getline(cin,s.name);

   cout << "ID:";

   cin >> s.id;

   cout << "Write the 4 tests grades of the student separated by space :";

   for (int i = 0; i<4; i++)

       cin >> s.grades[i];

}

//definition of the function of average

double inputAvg(Student s){

   double summation;

   int temporary;

   double average;

   for (int i = 0; i<4; i++){  

      for (int j = i; j<4; j++){

         if (s.grades[j] > s.grades[i]){

             temporary = s.grades[i];

             s.grades[i] = s.grades[j];

             s.grades[j] = temporary;

         }

      }

    }

    summation = 0;

    for (int i = 0; i<3; i++){

        summation = summation + s.grades[i];  

    }

    average = summation/3;

    return average;

}

void disp(Student *s){

   cout << s->name << endl;

   cout << s->id << endl;

   for (int i = 0; i<4; i++)

       cout << s->grades[i] << " ";

   cout << endl;

   cout << "Average :" << inputAvg(*s) << endl;

   

}

int main(){

  Student st;

  int ch;

  while(true){

      inputData(st);

      disp(&st);

      cout << " '1' to continue '0' to exit :";

      cin >> ch;

      if (ch == 0)

         break;      

  }

  return 0;

}

6 0
3 years ago
The ________ feature introduced by instant messaging shows whether a person is logged in and available to answer a question, pic
tester [92]

Answer:

The correct approach is "Presence awareness".

Explanation:

  • The willingness, at designated occasions, to see which one is available on the internet. When using the IM framework, that very many IM systems show a list of user groups attached to the system. A current model of the IGI Social website is being used by oneself.
  • With either the growing prevalence of Internet chat apps, a Presence Awareness model has been proposed by German IT professionals.
5 0
3 years ago
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