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Art [367]
3 years ago
8

Tom jogged 3/7 mile on monday and 2/6 mile om Tuesday.how much farther did Tom jog on monday than Tuesday

Mathematics
1 answer:
Volgvan3 years ago
5 0

3/7 (0.428571) Miles on Monday


2/6 = 1/3 (.333333) Miles on Tuesday


Subtract both numbers


.428571 - .333333 +


[Answer]: 0.095238


or 2/21 More miles on Monday.

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9 1/2 divided by 3 7/10
OleMash [197]

Solution:

<u>Convert the fractions into improper fractions and solve.</u>

  • 9 1/2 ÷ 3 7/10
  • => 19/2 ÷ 37/10
  • => 19/2 x 10/37
  • => 19 x 5/37
  • => 95/37

<u>Convert the fraction into mixed fraction (Not required):</u>

  • => 95/37 = 37/37 + 37/37 + 21/37
  • => 1 + 1 + 21/37
  • => 2 + 21/37
  • => 2 21/37

The solution to the problem is 2 21/37.

8 0
2 years ago
Read 2 more answers
750 tickets were sold for a game for a total of $1,400.00. If adult tickets sold for $2.50 and children's tickets sold
postnew [5]

Answer:

They sold 750

adult tickets is 275 and...

children's tickets is 475

3 0
3 years ago
Segment AB has endpoints A(–4, 6) and B(1, 4). After a dilation, centered at the origin, the image of A is (–6, 9). Without meas
Ksivusya [100]
With A and its image one can get the dilation factor;
That is dilation scale factor = -6/-4 or 9/6 = 3/2
Therefore, to get the image of B we multiply the coordinates of B by the dilation factor; 
(1,4) 3/2 = (1.5, 6)
Thus the image of B = (1.5,6)
4 0
3 years ago
Read 2 more answers
how much does a bag of wood chips weighs 12.4 pounds how much does a bad that contains .42 as many wood chips weigh
Law Incorporation [45]

Answer:

5.208 lbs

Step-by-step explanation:

12.4 lbs times 0.42 is 5.208 lbs

it is simple

3 0
3 years ago
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An object has been thrown straight up into the air. The formula h = vt - 16t^2 gives the height of the object above the ground a
Oxana [17]

Answer:

8 seconds.

Step-by-step explanation:

To solve this question, we need to find the time, t, when h = 0, that is, when the height of the object above the ground is 0 feet.

Substituting v = 128 feet per second and h = 0 gives  the quadratic:

0 = 128t - 16t^{2}

Since 128 is divisible by 16, it can be reduced to 0 = 16(8t - t^{2}).

We must now solve for t.

We can easily see that one answer to the equation is 0,

8(0) - (0)^{2} = 0 (we need not concern ourselves with the 16 outside of the parenthesis as in the equation above, since 16 multiplied by 0 is 0). However this is the time the object is released into the air.

The second answer, t = 8 is also easy to see by inspection:

8(8) - (8)^{2} = 0.

Therefore the object lands 8 seconds after it is thrown.

6 0
3 years ago
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