There is no given data table but based on the question, the reaction is
xy <=> x + y
If we let M as the initial concentration of xy and c as the in the concentration after the dissociation, then we can use the ICE method
xy <=> x + y
I M
C -c c c
-----------------------------
E M-c c c
Solve for c using
Kc = c(c) / (M - c)
And the concentration of the xy, x, and y can then be determined
Simplifying
12x + 10 + 3 + 8x = 0
Reorder the terms:
10 + 3 + 12x + 8x = 0
Combine like terms: 10 + 3 = 13
13 + 12x + 8x = 0
Combine like terms: 12x + 8x = 20x
13 + 20x = 0
Solving
13 + 20x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-13' to each side of the equation.
13 + -13 + 20x = 0 + -13
Combine like terms: 13 + -13 = 0
0 + 20x = 0 + -13
20x = 0 + -13
Combine like terms: 0 + -13 = -13
20x = -13
Divide each side by '20'.
x = -0.65
Simplifying
x = -0.65
Answer:
It is A
Step-by-step explanation:
2x + y = 5
y + 3 = 2x
From equation 2:
y = 2x - 3
Substituting in the first equation:
2x + 2x - 3 = 5.
S = 4
3(10) = 10 + 5s
30 = 10 + 5s
30 - 10 = 5s
20 = 5s
20 ÷ 5 = s
4 = s
