Temperature at noon: Tn=-2.9 f
Rate: r=+1.3 f/h
Total decreased: d=-3.7 f
Temperature at midnight: Tm=?
Tm=Tn+r(6 p.m.-12 m)+d
Tm=-2.9 f+(1.3 f/h)(18 h-12 h)+(-3.7 f)
Tm=-2.9 f+(1.3 f/h)(6 h)-3.7 f
Tm=-2.9 f+7.8 f-3.7 f
Tm=1.2 f
Answer: T<span>he temperature at midnight was 1.2 f</span>
Answer:
≈ 1800 mm³
Step-by-step explanation:
Volume of the figure above will be given by the formula
Cross section area × length
In this case;
Cross section area will be;
Area of the square + area of the two semi circles
12× 12 + 2(3.14 × 6 ×6/2)
= 144 + 3.14 ×36
= 257.04 mm²
Volume = Cross section area × Length
= 257.04 × 7
= 1799.28 mm³
<u> ≈ 1800 mm³</u>
Answer:
y = 4
Step-by-step explanation:
The maximum value occurs at the vertex
vertex = (2, 4 )
when x = 2 the maximum value is y = 4
Since 2+8 =10 you would just have 3 left to add so it would be 10+3=13
