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4 years ago

11

How do i find the area of a trapezoid? please make your answer simple yet descriptive...

1 answer:

Vera_Pavlovna [14]4 years ago

4 0

A = a+b/2 x h
Add sides a and b then divide by 2
After that multiply by the h

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Roman is born in the year 123 BC and dies at the age of 74 years. Use a negative number to express the year in which he dies

Stells [14]

Answer:

-49 or 49 BC

hope that this helps

7 0

3 years ago

Write a quadratic equation in the form x² + bx+c=0 that has the following

vfiekz [6]

Answer:

x^2-6x+5

Step-by-step explanation:

To have roots at x=5 and x=1 you need to write is as follows

(x-5)(x-1)

you then need to multiply these two and get

x^2-6x+5

7 0

3 years ago

HELP!!!!<br><br> What is the surface area of the figure below?

GuDViN [60]

surface area= perimeter x height + 2b

s= pxh+2b

example: 18(8)+2(12)

explain: 18 is the perimeter and 8 is the height then you have to add the base times 2

8 0

3 years ago

Cidnee is weighing combinations of geometric solids. She found that 4 cylinders and 5 prisms weigh 32 ounces and that 1 cylinder

vitfil [10]

Answer:

The weights of each cylinder and prism are 3 and 4 ounces, respectively.

Step-by-step explanation:

Let be $x$ and $y$ the masses of a cylinder and a prism, measured in ounces, respectively. After a careful reading of the statement we get the following linear equations by interpretation:

i) <em>She found that 4 cylinders and 5 prisms weigh 32 ounces:</em>

$4\cdot x +5\cdot y = 32\,oz$ (Eq. 1)

ii) <em>And that 1 cylinder and 8 prisms weigh 35 ounces:</em>

$x + 8\cdot y = 35\,oz$ (Eq. 2)

Now we solve the system of linear equations algebraically:

From (Eq. 2):

$x = 35 - 8\cdot y$

(Eq. 2) is (Eq. 1):

$4\cdot (35-8\cdot y) + 5\cdot y = 32$

$140-32\cdot y +5\cdot y = 32$

$32\cdot y - 5\cdot y = 140-32$

$27\cdot y = 108$

$y = 4\,oz$

From (Eq. 2):

$x = 35 - 8\cdot (4)$

$x = 35 - 32$

$x = 3\,oz$

The weights of each cylinder and prism are 3 and 4 ounces, respectively.

4 0

3 years ago

Hey what's the answer ?<br><img src="https://tex.z-dn.net/?f=%28%20%7By%7D%5E%7B2%7D%20%20%2B%20%20%5Cfrac%7B5%7D%7B7%7D%20%29%2

3241004551 [841]

Answer: $y^4$ + $\frac{-73}{35}y^2$ - $2$

Step-by-step explanation:

Use FOIL:

$y^4$ + $\frac{-14}{5}y^2$ + $\frac{5}{7}y^2$ + $\frac{-70}{35}$

Make $\frac{-14}{5}y^2$ and $\frac{5}{7}y^2$ have the same numerator:

$\frac{-14*7}{5*7}y^2 =\frac{-98}{35}y^2$

$\frac{5*5}{7*5} y^2=\frac{25}{35} y^2$

Then add like terms and simplify:

$y^4$ + $\frac{-98}{35}y^2$ + $\frac{25}{35} y^2$ + $\frac{-70}{35}$

$y^4$ + $\frac{-73}{35}y^2$ - $2$

7 0

3 years ago

Read 2 more answers