The sum of the first 8 terms of a geometric sequence with 4 as the first term and a common ratio of 3 is
2 answers:
9514 1404 393
Answer:
13120
Step-by-step explanation:
The sum of terms of a geometric series is ...
Sn = a1·(r^n -1)/(r -1)
You have n=8, a1=4, r=3, so the sum is ...
S8 = 4·(3^8 -1)/(3 -1) = 2(3^8 -1) = 13,120
Answer:
<h2><u>1</u><u>3</u><u> </u><u>1</u><u>2</u><u>0</u></h2>
Step-by-step explanation:
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