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GenaCL600 [577]
3 years ago
9

TRANSLATE INTO AN INEQUALITY!! seven subtracted from c is less than -30

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

7-c < 30

Step-by-step explanation:

its in your question.

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How do you get 2 to 5 in multiplying and dividing​
Ksenya-84 [330]

Answer

Multiply 2.5

Step-by-step explanation:

2*2.5=5

8 0
3 years ago
409381886 rounded to the nearest hundred thousand
rewona [7]
The answer is 409,400,000 because 8 (to the right of 3) is more than 5, so you round up
5 0
3 years ago
Read 2 more answers
Consider a two-station production line in which no inventory is allowed between stations (i.e., the stations are tightly coupled
Alona [7]

Answer:

a) Capacities : station 1 = 3.5 , station 2 = 3.5

  Both stations have the same capacity

b) 3.5 ( it does not differ from a )

c) The value will double i.e. 3.5 * 2 = 7

Step-by-step explanation:

<u>a) compute the capacity of each station and show if the line is balanced </u>

for station 1

Units :            1 ,2 ,3, 4 ,5, 6

probabilities :   1/6 ( same value for all units )

for station 2

units :             3, 4

probabilities :  1/2   1/2

Capacity of station 1= ( 1/6 * 1 ) + ( 1/6 *2 ) + ( 1/6 *3) + (1/6 *4) + (1/6*5) + (1/6*6 )

                                =  3.5  

Capacity of station 2 = ( 1/2 * 3 ) + ( 1/2 * 4 )

                                  = 3.5

∴ both stations have the same capacity

B) Expected throughput of the line

= Min( capacity of station 1 , capacity of station 2 )

= 3.5  ( It does not differ from a )

C) When an additional identical machine is added to both stations the expected throughput of the line will be doubled

i.e. expected throughput = ( 3.5 ) * 2 = 7

6 0
3 years ago
find the magnitude of two forces f1 and f2 such that at right-angle to each other, their resultant is √13N. Also, if the two for
serious [3.7K]
This can be solved a couple of ways. One way is to use the Pythagorean theorem to write equations for the magnitude from the components of the forces. That is what was done in the graph here.

Another way is to use the Law of Cosines, which lets you make direct use of the angle between the vectors.
.. 13 = a^2 +b^2 -2ab*cos(90°)
.. 19 = a^2 +b^2 -2ab*cos(120°)
Subtracting the first equation from the second, we have
.. 6 = -2ab*cos(120°)
.. ab = 6

Substituting this into the first equation, we have
.. 13 = a^2 +(6/a)^2
.. a^4 -13a^2 +36 = 0
.. (a^2 -9)(a^2 -4) = 0
.. a = ±3 or ±2

The magnitudes of the two forces are 2N and 3N, in no particular order.

5 0
3 years ago
A plane averaged 500 mph on a trip going east, but only 200 mph on the return trip. The total flying time in both directions was
adoni [48]

Let's assume time taken by plane on one way distance as 't'

The total flying time in both directions was 10.5 hr

so, time taken in other direction =10.5-t

now, we are given

A plane averaged 500 mph on a trip going east

so, total distance of one way is

=500t

total distance of other way is

=200(10.5-t)

now, we can that distance is same from both sides

so, we get

500t=200(10.5-t)

now, we can solve for t

500t=2100-200t

700t=2100

t=3

now, we can find one way distance

=500\times 3

=1500miles..............Answer

6 0
3 years ago
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