distance between two points is [(x2-x1)^2 +(y2-y1)^2]^1/2
I.e,[{5-1)^2+(0-3)^2]^1/2
[16+9]^1/2
[25]^1/2
5
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j. Hence, The vector AB is 16i + 12j.
<h3>How to find the vector?</h3>
If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j.
magnitude

Unit vector in direction of resultant = (4i + 3j) / 5
Vector of magnitude 20 unit in direction of the resultant
= 20 x (4i + 3j) / 5
= 4 x (4i + 3j)
= 16i + 12j
Hence, The vector AB is 16i + 12j.
Learn more about vectors;
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Sorry I don’t know the answer and the question to
0.08 if 4 divided by 50
12.5 if 50 divided by 4
Answer:
m = 4/3
Step-by-step explanation:
To find the slope of a line use the formula, where "m" means slope:

*You don't need to show this part on paper*
Choose which point you want to be point 1 and point 2. Remember the points are written (x, y).
Point 1: (-2, 1) x₁ = -2 y₁ = 1
Point 2: (4, 9) x₂ = 4 y₂ = 9
Substitute the coordinates into the formula:
*Show this part on paper*

Simplify
Reduce by dividing by 2
Slope
The slope of the line is 4/3