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EastWind [94]
3 years ago
12

John has a $1000 bond with a 3% coupon. How much interest will John receive for this bond every 6 months?

Mathematics
1 answer:
IgorLugansk [536]3 years ago
4 0
The interest of the bond  for 6 months is $15. This is computed as 3% of 1000 is $30. Then since it is only for 6 months, $30 divided by 12 months and multiplied by 6, which is equal to $15
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-6 &gt; -9<br><br> Which best explains whether the inequality is true or false?
Natali [406]

Answer:

-6 on a number line is closer to 0 which make sit greater while -9 is farther away which makes it less than -6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Luke bought 256256256 ounces of strawberries. He divided them evenly between 888 different pies. How many pounds of strawberries
SIZIF [17.4K]

Answer:

2 pounds.

Step-by-step explanation:

We have been given that Luke bought 256 ounces of strawberries. He divided them evenly between 8 different pies. We are asked to find the pounds of strawberries that Luke put on each pie.

First of all, we will convert 256 ounces into pounds.

We know that 1 pound equals 16 ounces. To convert 256 ounces into pounds, we need to divide 256 by 16.

\text{256 ounces}=\frac{256}{16}\text{ pounds}=16\text{ pounds}

Now we will divide 16 pounds by 8 to find number of strawberries put on each pie.

\text{Pounds of strawberries on each pie}=\frac{16}{8}

\text{Pounds of strawberries on each pie}=2

Therefore, Luke put 2 pounds strawberries on each pie.

4 0
3 years ago
Ex 7) Imagine a mile-long bar of metal such as the rail along railroad tracks. Suppose that the rail is anchored on both ends an
Fantom [35]

9514 1404 393

Answer:

  about 44.5 feet

Step-by-step explanation:

We can write relations for the height of the rail as a function of initial length and expanded length, but the solution cannot be found algebraically. A graphical solution or iterative solution is possible.

Referring to the figure in the second attachment, we can write a relation between the angle value α and the height of the circular arc as ...

  h = c·tan(α) . . . . . . where c = half the initial rail length

Then the length of the expanded rail is ...

  s = r(2α) = (c/sin(2α)(2α) . . . . . . where s = half the expanded rail length

Rearranging this last equation, we have ...

  sin(2α)/(2α) = c/s

It is this equation that must be solved iteratively. We find the solution to be ...

  α ≈ 0.0168538794049 radians

So, the height of the circular arc is ...

  h = 2640.5·tan(0.0168538794049) ≈ 44.4984550191 . . . feet

The rail will bow upward by about 44.5 feet.

_____

<em>Additional comments</em>

Note that s and c in the diagram are half the lengths of the arc and the chord, respectively. The ratio of half-lengths is the same as the ratio of full lengths: c/s = 2640/2640.5 = 5280/5281.

We don't know the precise shape the arc will take, but we suspect is is not a circular arc. It seems likely to be a catenary, or something similar.

__

We used Newton's method iteration to refine the estimate of the angle from that shown on the graph. The iterator used is x' = x -f(x)/f'(x), where x' is the next guess based on the previous guess of x. Only a few iterations are required obtain an angle value to full calculator precision.

3 0
3 years ago
Tickets for the school play sell for $4 each. Which graph shows the relationship between the number of tickets solo
Xelga [282]

Answer:

I do not see all the graphs but it would be the reverse of what is shown for A. graph. The tickets sold to total income would have to be a 1:4 ratio where every 4 dollar leap in the y-axis is a one point (1 unit change in x).

Step-by-step explanation:

8 0
3 years ago
The diagram shows the ratio of trees Maeve plants to the trees she harvests.
AnnZ [28]

Answer:

WEDNESDAY: 45 planted.

THURSDAY: 22 Harvested.

Step-by-step explanation:

Based on the information given in the problem, Maeve plants 5 trees for every 2 tree she harvests. Then the ratio can be expressed as following:

5:2 or \frac{5}{2}

Then, you can complete the values in the table as you can see below:

<u>WEDNESDAY</u>

\frac{5}{2}=\frac{planted}{18}\\\\planted=\frac{18*5}{2}\\\\planted=45

<u>THURDAY</u>

\frac{5}{2}=\frac{55}{harvested}\\\\(harvested)(\frac{5}{2})=55\\\\harvested=\frac{55*2}{5}\\\\harvested=22

6 0
3 years ago
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