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lubasha [3.4K]
3 years ago
6

At midnight, the temperature in a city was 5 degrees Celsius. The temperature was dropping at a steady rate of 2 degrees Celsius

per hour.
Write an inequality that represents t, the number of hours past midnight, when the temperature was colder than -4 degrees Celsius. Explain or show your reasoning.
Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:

t > 4.5

Step-by-step explanation:

T = 5 - 2t

is the equation for the temperature after midnight.

-4 = 5 - 2t  is the point of interest

-9 = -2t

t = 4.5 hrs  so 4:30 is the time the temperature reaches -4

t > 4.5 hrs covers all the time that the temperature is less than -4

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Erin was completing the square of the quadratic function in order to find the extreme value. What is the next step in the proces
Lady bird [3.3K]

Step-by-step explanation:

ax^2+bx+c=0

a=leading term

ok so if the leading term is positive then opens up and has a <u>min</u>

if leading term is negative then opens down and has a <u>max</u>

leading term is positive

1x^2+8x

it has a min

to complete the square, move c aside take 1/2 of b and square it

b=8

8/2=4

4^2=16

now add that to both sides

x^2+8x+16+6=0+16

factor perfect square

(x+4)^2+6=16

subtract 6

(x+4)^2=10

subtract 10

(x+4)^2-10=0

vertex aka min or max is (h,k) when ou have

y=a(x-h)+k

h=-4

k=-10

7 0
3 years ago
Pls help me if your good at math I’ll mark brainliest
scoray [572]
Rotation about the origin
3 0
3 years ago
the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function
Likurg_2 [28]

The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about area here:

brainly.com/question/27683633

#SPJ4

3 0
2 years ago
An automobile manufacturer is concerned about a possible recall of its best-selling four-door sedan. If there were a recall, the
andrew11 [14]

Answer:

0.27

Step-by-step explanation:

Suppose A is the event of defect in the brake system and B is the event of defect in the fuel system,

We have given,

P(A) = 0.25,

P(B) = 0.17

P(A∩B) = 0.15 ( the probability of defects in both systems simultaneously is 0.15 ),

We know that,

P(A∪B) = P(A) + P(B) - P(A∩B)

= 0.25 + 0.17 - 0.15

= 0.27

Hence, the probability that the defect is the brakes or the fueling system is 0.27.

8 0
3 years ago
The sale is being held from 11 a.m to 7 p.m on sunday, and from 9 a.m to 7 p.m on monday. How many hours will the sale last?​
PSYCHO15rus [73]
8+10=18as your final answer
3 0
3 years ago
Read 2 more answers
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