Answer:
30064, if round trip multiply by 2
Step-by-step explanation:
so this is just multiplication. I am not sure if its round trip, but if its not then its just the 7516 times 4= 30064
We can start by finding the gradient of LM

Two perpendicular lines will meet the requirement

×

=-1
Two parallel lines have equal gradients
NM is perpendicular to LM, hence the gradient of NM is -1
KN is a line that is parallel to NM, hence the gradient is 1
KL is perpendicular to LM, hence the gradient of KL is -1
Answer:
Step 1: Factor left side of equation.
(5x−1)(3x−5)=0
Step 2: Set factors equal to 0.
5x−1=0 or 3x−5=0
x=
1
/5
or x=
5
/3
Answer:
n, they will drive from Fort Worth to San Antonio, a distance of 229 miles, to visit his grandparents. On the way back, Mike reverses his trip and travels from San Antonio to Dallas through Forth Worth. Write one equation to show the distance traveled from Dallas to San Antonio, and a second equation to show the distance traveled from San Antonio to Dallas. What do you notice about the distance traveled each w
Step-by-step explanation:
n, they will drive from Fort Worth to San Antonio, a distance of 229 miles, to visit his grandparents. On the way back, Mike reverses his trip and travels from San Antonio to Dallas through Forth Worth. Write one equation to show the distance traveled from Dallas to San Antonio, and a second equation to show the distance traveled from San Antonio to Dallas. What do you notice about the distance traveled each w
2)
P(4,-4) -->(-4, 7)
4 - 8 = -4 -------->left 8
-4 + 11 = 7 -------->up 11
Answer: left 8; up 11
3)
C(3,-1) , left 4 up 1
3 - 4 = -1 -------->left 4
-1 + 1 = 0 -------->up 1
a)
(x , y) -->(x - 4 , y +1)
C(3, -1) -->C'(-1 , 0)
b)
(x , y) --> (x - 4, y + 1); (-1 , 0)