MCV = Hct × 10/RBC (84-96 fL) •Mean corpuscular Hb (MCH) = Hb × 10/RBC (26-36 pg) •Mean corpuscular Hb concentration (MCHC) = Hb × 10/Hct (32-36%) A rapid method of determining whether cellular indices are normocytic and normochromic is to multiply the RBC and Hb by 3.
Answer:
Correct response: Tachycardia; hypotension
Explanation:
A low cardiac output would be exhibited by tachycardia and hypotension.
Answer:
Virus transmission is affected by a number of factors, including environmental determinants, host behavior, host defense mechanisms, and virus infectivity.
Explanation:
Answer:
i dont know
Explanation:
thank u that u thanked me
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Answer:
Appropriate Question:-
The output for a 60kg woman who runs up a 3m high flight of stairs in 3.5 sec.starting from rest but having a final speed of 2 m/s.
Given:-
Mass of woman=m=60kg.
Height=h=3m
Time=t=3.5secs.
To find :-
Here we want to calculate the output for a woman
Here first we should calculate work done first.
work \: done = mghworkdone=mgh
Applying the values,
work \: done = 10 \times 60 \times 3workdone=10×60×3
Work done= 1800Joule.
Now , lets calculate power,
power = \frac{workdone}{time \: taken} power=
timetaken
workdone
Now,
Applying the values ,
power = \frac{1800}{3.5} power=
3.5
1800
Power =514.2857 watt.
Hope it helps u mate .
Thank you .
