Answer:
D) 26 two-pointers and 15 three-pointers
Step-by-step explanation:
x= 2 pointers
y= 3 pointers
Make a system of equations:
x=41-y
2x+3y=97
Plug In:
2(41-y)+3y=97
82+y=97
y= 15 (three point shots)
Check:
15(3)=45
97-45=52
52/2=26
x=26 (2 point shots)
Graphing quadratic formulas is not always exact. Completing the square will be exact.
In ijk notation, the boat has velocity (relative to the water)
![\vec v_{B/W}=(22\,\vec\imath)\dfrac{\rm km}{\rm hr}](https://tex.z-dn.net/?f=%5Cvec%20v_%7BB%2FW%7D%3D%2822%5C%2C%5Cvec%5Cimath%29%5Cdfrac%7B%5Crm%20km%7D%7B%5Crm%20hr%7D)
and the current has velocity (relative to the Earth)
![\vec v_{W/E}=(10\cos225^\circ\,\vec\imath+10\sin225^\circ\,\vec\jmath)\dfrac{\rm km}{\rm hr}](https://tex.z-dn.net/?f=%5Cvec%20v_%7BW%2FE%7D%3D%2810%5Ccos225%5E%5Ccirc%5C%2C%5Cvec%5Cimath%2B10%5Csin225%5E%5Ccirc%5C%2C%5Cvec%5Cjmath%29%5Cdfrac%7B%5Crm%20km%7D%7B%5Crm%20hr%7D)
The boat's "true" velocity (relative to the Earth) satisfies
![\vec v_{B/E}=\vec v_{B/W}+\vec v_{W/E}](https://tex.z-dn.net/?f=%5Cvec%20v_%7BB%2FE%7D%3D%5Cvec%20v_%7BB%2FW%7D%2B%5Cvec%20v_%7BW%2FE%7D)
so that
![\boxed{\vec v_{B/E}=(14.93\,\vec\imath-7.07\,\vec\jmath)\dfrac{\rm km}{\rm hr}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cvec%20v_%7BB%2FE%7D%3D%2814.93%5C%2C%5Cvec%5Cimath-7.07%5C%2C%5Cvec%5Cjmath%29%5Cdfrac%7B%5Crm%20km%7D%7B%5Crm%20hr%7D%7D)
which translates to a speed of about 16.5 km/hr in a direction of 25.48º South of East.
Answer:
2.25
Step-by-step explanation:
25% is a quarter
therefore a quarter of 9 is
0.25×9
=2.25
The answer is there what u need help with?