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2 years ago

How do you solve 9x≥80? Please help!

2 answers:

Lelu [443]2 years ago

6 0

You divide each term by 9 and simplify
and the answer is x≥80/9
hope this helps

5 0

x ≥ -80/3 is the answer

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sergejj [24]

Answer:

$\frac{\sqrt3}{2}$

Step-by-step explanation:

$sin(A)=\frac{1}{2}$

$A = \frac{\pi}{6}$ //this is retrieved from looking at the unit circle

$cos(A) = cos(\frac{\pi}{6}) = \frac{\sqrt3}{2}$

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Nezavi [6.7K]

Answer:

5a+30

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