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Galina-37 [17]
3 years ago
15

How do you solve 9x≥80? Please help!

Mathematics
2 answers:
Lelu [443]3 years ago
6 0
You divide each term by 9 and simplify 
and the answer is x<span>≥</span>80/9
hope this helps

                                

AysviL [449]3 years ago
5 0
 <span>x ≥ -80/3 is the answer 

</span>
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F(x) = x2<br> What is f(x) + f(x) + f(x)?
Yuliya22 [10]

Answer:

if you meant x squared the answer is 3x^2

Step-by-step explanation:

If f(x) is equal to 2x you can substitute x squared for f(x) and that would be x squared+x squared+x squared which is 3x^2

6 0
3 years ago
Read 2 more answers
The sum of two numbers is 48. If one third of one number is 5 greater than one sixth of another number, which of the following i
lubasha [3.4K]
<span>The sum of two numbers is 48.
a + b = 48
;
If one third of one number is 5 greater than one sixth of another number,
a = b + 5
multiply both sides by 6, cancel the fractions
2a = b + 30
2a - b = 30
</span><span>use elimination to solve this
a + b = 48
2a - b =30
-------------Addition eliminates b, find a
3a = 78
a = 
a = 26
then
26 + b = 48
b = 48 - 26

b = 22</span>
5 0
3 years ago
Give the slope and the y-intercept of the line y = – 6x– 4. Make sure the y-intercept is written as
jonny [76]

Answer:

Step-by-step explanation:

Slope = -6

Y-intercept (0, -4)

7 0
3 years ago
two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they
Lerok [7]
Let's make,
mechanic #1's rate = x
mechanic #2's rate = y

* Their rate is dollars per hour ($/hr)

mechanic #1 worked for 20 hours (hr × $/hr = $)
20x = money earned by mech#1

and mechanic #2 worked for 5 hours
5y = money earned by mech#2

together they charged a total of $1150. So the amount of money earned by both mechanics.

20x + 5y = 1150

the sum of the two rates was $95 per hour.

x + y = 95

which means
x = 95 - y

plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.

20(95 - y) + 5y = 1150

solve for y

1900 - 20y + 5y = 1150
1900 - 15y = 1150
-15y = 1150 - 1900
-15y = -750
y = -750/-15
y = 50 $/hr

Now use this to solve for x

x + y = 95
x + 50 = 95
x = 95 - 50
x = 45 $/hr

mech#1 charged 45$/hr
mech #2 charged 50$/hr
7 0
3 years ago
How do you work out this problem, step by step please I am so lost. Year Average Household Income (before taxes) Food Housing Tr
Hitman42 [59]

Answer:

(a)Food-12%

9b)Transportation-17%

Step-by-step explanation:

In the Year 2000

  • Average Household Income (before taxes)=$44,649
  • Amount Spent on Food =$5,158
  • Amount Spent on Transportation=$7,417

Therefore:

(a)Percentage of the average household income in 2000 was spent on food

=\dfrac{5158}{44649} \times 100\\\\=11.55\%\\\\\approx 12\% $(to the nearest percent.)

(b)Percentage of the average household income in 2000 was spent on transportation

=\dfrac{7,417}{44649} \times 100\\\\=16.6\%\\\\\approx 17\% $(to the nearest percent.)

3 0
3 years ago
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