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4 years ago

8

Write a problem about a group of objects in your classroom

2 answers:

fredd [130]4 years ago

6 0

Emma has six pencils. If she gives some pencils to two people, how many pencils and ends up with none, how many pencils did she give to each person?

erik [133]4 years ago

3 0

The seats in the classroom form a square pattern
of four columns and six rows.

There is one of these mystery objects in every seat
between the hours of 9:00 AM and 12:00 Noon,
and also between the hours of 1:00 PM and 4:30 PM.

a). How many objects are there in seats at 12:45 PM ?

b). How many objects are there in seats at 2:07 PM ?

c). What do you think the mystery objects are ?

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Pre-Calculus - Systems of Equations with 3 Variables please show work/steps

Tatiana [17]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0

3 years ago

A company is designing a new cylindrical water bottle. The volume of the bottle will be 219 cm cubed. The height of the water bo

Elden [556K]

Answer: I think its 2.29

Step-by-step explanation:

7 0

3 years ago

Find x and y. Remember that a + bi = c + di exactly when a = c and b = d. 8 = (4+8i)(x+yi)

irakobra [83]

<span>x+yi = <span>8/(<span>4+8i)</span></span></span><span>x+yi = <span>2/(<span>1+2i)</span></span></span><span>x+yi = <span>2/(<span>1+2i) </span></span>× (<span><span>1−2i)/(</span><span>1−2i)</span></span></span><span>x+yi = (<span><span>2−4i) /</span>5</span></span><span><span>x+yi = <span>2/5</span>−<span>4/5</span>i

x= 2/5
y= -4/5i

</span></span>

3 0

4 years ago

Solve the following equation:

kirza4 [7]

Answer:

The answer is A

Step-by-step explanation:

4(x-3=)=48-8x

4(5-3)=48-8*5

20-12=8 48-40=8

8=8

Hope this answers your question

8 0

3 years ago

Read 2 more answers

A fountain can hold 53,000 deciliters of water. How many kiloliters is this?

Simora [160]

One deciliter is 0.0001 kiloliter. Therefore, 53,000 deciliters of water would equal 5.3000 kiloliters

4 0

3 years ago