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V125BC [204]
2 years ago
10

8m + 2/10 + 3n + 4/10 + 6m - 2n

Mathematics
1 answer:
erik [133]2 years ago
4 0

Answer:

14m+n+3/5

Hope it helped!

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What's 2|-9| - |-2|?
UNO [17]

Answer:

16

Step-by-step explanation:

First, simplify by finding the absolute values:

2|-9| - |-2|

2(9) - (2)

Then, simplify this by multiplying 2 and 9:

18 - 2

= 16

So, the answer is 16

3 0
2 years ago
What is the common factor of each term in the expression 2b + 5b?”
stellarik [79]
The common factor is b since they both share it.
Hope this helps
7 0
3 years ago
Find the measure of 46.<br> 70*110°<br> 46<br> o<br> 66 = [?]
IgorLugansk [536]
Angle 6 is 110 degrees
5 0
3 years ago
Read 2 more answers
Wendy is creating a large soup based on a recipe. Her recipe calls for 3/4 of a pint of milk, but she only has 5/8 of a pint of
mina [271]
Wendy needs 1/8 more to make her soup

5 0
3 years ago
Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce
34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)

= 1 - P(z \leq -2)

Calculation the value from standard normal z table, we have,  

P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)

Calculation the value from standard normal z table, we have,  

P(x < 23.7) =0.159= 15.9\%

15.9% of of the boxes weigh less than 23.7 ounces.

7 0
3 years ago
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