3 years ago

What is the area of this triangle?

1 answer:

3 0

$\text {Area = } \dfrac{1}{2} ABsin C$

$\text {Area = } \dfrac{1}{2} (3.2)(4.7)sin (62 \textdegree)$

$\text {Area = } 6.64 \ yd^2$

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