Answer:
2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)
Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?
ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol
Answer:
ST, RS, TR
Step-by-step explanation:
(i entered it and it was right)
A = bh/2
2a = bh
2a/b = h
h = 2a/b
Answer:-
x=-5/2
Step-by-step explanation:
x+2/3=-1/6
after cross-mutiplying,
6(x+2)=-3
6x+12=-3
6x=-3-12
6x=-15
x=-15/6
x=-5/2
hope this helps u!!