Subtract g(x) from f(x): (x²+3x-1)-(x³+4x²+1)=-x³-3x²+3x-2
C is the correct answer.
Let L be the low copper alloy and H be the high copper alloy.
We need 0.15L + 0.60H = 0.42 and L + H = 100
L=100 - H
Substituting this into the second equation for L, we get:
0.15(100-H) + 0.60H = 0.42(H+L)
15 - 0.15H + 0.60H = 0.42(H+100-H)
15 + 0.45H = 0.42(100)
0.45H = 42 - 15 = 27
H = 27/.45 = 60 lbs
Back substitution, L = 40 lbs.
Answer:
Step-by-step explanation:
Use the Product Rule (uv)' = uv' + u'v
20%
7/35 = 1/5 when simplified all the way
1/5 = 20%
