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Alexxandr [17]
3 years ago
7

The length of a rectangle is 24 units. Can the perimeter P of the rectangle be 60 units when its width w is 11 units?​

Mathematics
1 answer:
marishachu [46]3 years ago
5 0
No it cannot because the perimeter is the sum of all the sides and a rectangle has 4 sides so 24x2 + 11x2 = 70. So the perimeter would be 70 not 60.

Hope this helps :)
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Charles is 20% heavier than Edith. If Charles weighs 60kg, what is Edith's weight?​
ddd [48]

Charles' weight = Edith's weight + 20% of Edith's weight

We'll use a variable to represent Edith's weight, x.

The decimal form of 20% is 0.2.

60 = x + 0.2x

60 = 1.2x

x = 50

Edith's weight is 50kg.

Hope this helps!

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2 years ago
A cone is placed inside a cylinder. The cone has half the radius of the cylinder, but the height of each figure is the same. The
Yuliya22 [10]
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7 0
3 years ago
Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
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Ilia_Sergeevich [38]

Answer:

I think the answer is 8

Step-by-step explanation:

7 0
3 years ago
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