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RUDIKE [14]
3 years ago
8

Women's heights are normally distributed with mean 63.5 in and standard deviation of 2.5 in. A social organization for tall peop

le has a requirement that women must be at least 70 in tall. What percentage of women meet that requirement?
Mathematics
1 answer:
Vanyuwa [196]3 years ago
8 0
First, ask yourself how far way is 70 from the mean of 63.5? It is equal to 70 - 63.5 = 6.5 inches. 

Next, ask yourself how many standard deviations is this? Well, every standard deviation equals 2.5 inches, so there are 6.5 / 2.5 = 2.6 standard deviations. So, 70 is exactly 2.6 standard deviations to the right of the mean. 

Finally, you can use the Standard Normal to find the answer P(X>70) since this is equivalent to: 

<span>P(z > 2.6) = 0.0054 or 0.54% of women will be taller than 70 inches. 

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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Answer:

The slope of RT is: m = 1

Step-by-step explanation:

Given

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\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-3,\:1\right),\:\left(x_2,\:y_2\right)=\left(2,\:6\right)

m=\frac{6-1}{2-\left(-3\right)}

Refine

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Therefore, the slope of RT is: m = 1

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