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Pepsi [2]
3 years ago
14

You work 40 hours/week for 50 weeks and are given the option to be paid hourly or to go on salary. In which situation will you e

arn the most?
Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

40/50 weeks is the ans

plzzz give brainliest

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The graph shows the relationship between hours worked and total earnings for a store clerk. Let h represent hours worked and e r
Dovator [93]

Answer:

The answer is C.

Step-by-step explanation:

y = kx → e =

30

4

h → e = 7.5h

The independent variable is hours worked, h, and the dependent variable is total earnings, e. The independent variable is the input value of a function. The dependent variable is the output value of a function.

8 0
3 years ago
If 2 coins is flipped 200 time, how many times would youe expect to land on heads​
Art [367]

Answer:

200 times

Step-by-step explanation:

400÷2=200

because the next 200 would be landing on tails

6 0
3 years ago
Read 2 more answers
NEED HELP NOW 10 POINTS WILL MARK BRAINLIEST ANSWER PLZ ANSWER ALL 5 PHOTOS!!!!!
CaHeK987 [17]
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7 0
3 years ago
Sam has a collection of stamps. For every 18 dinosaur stamps, he has 12 airplane stamps. Sam wrote a ratio for dinosaur stamps t
const2013 [10]

Answer:

Given the ratio for dinosaur stamps to airplane stamp, the correct ratio is 18 : 12

Step-by-step explanation:

Dinosaur stamps = 18

Airplane stamps = 12

John wrote:

ratio of dinosaur stamps to airplane stamps = 12 to 18

Correct ratio:

ratio of dinosaur stamps to airplane stamps = 18 : 12

= 18/12

6 0
3 years ago
You have 42,784 grams of a radioactive kind of curium. If its half-life is 18 years, how much will be left after 72 years?
s344n2d4d5 [400]

Answer:

2,674.14 g

Step-by-step explanation:

Recall that the formula for radioactive decay is

N = N₀ e^(-λt)

where,

N is the amount left at time t

N₀ is the initial amount when t=0, (given as 42,784 g)

λ = coefficient of radioactive decay

  = 0.693 ÷ Half Life

  = 0.693 ÷ 18

  = 0.0385

t = time elapsed (given as 72 years)

e = exponential constant ( approx 2.7183)

If we substitute these into our equation:

N = N₀ e^(-λt)

= (42,787) (2.7183)^[(-0.0385)(72)]

= (42,787) (2.7183)^(-2.7726)

=  (42,787) (0.0625)

= 2,674.14 g

6 0
3 years ago
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