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SashulF [63]
3 years ago
5

Use the guess and check method to solve for the equation : 4(x+2)+2=14 please help need answer

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

4(x+2)+2=14

4x+8+2=14

4x+10=14

Subtract 10 from both sides

4x=4

Divide by 4 on both sides

x=1

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A magazine provided results from a poll of 1500 adults who were asked to identify their favorite pie. among the 1500 ​respondent
valentinak56 [21]

Answer:

0.01  is alpha level

Step-by-step explanation:

Given that a survey of a magazine of 1500 adults revealed that 12% chose chocolate pie.

i.e. p = proportion of people who like chocolate pie = 0.12

Margin of error = ±0.03

The value of   q  =1-\hat p , =1-0.12 = 0.88


The sample size n  is given as 1500. Therefore,  n=1500

The confidence level is given as 99%

Hence alpha = 1- confidence level


=1-0.99=0.01

Hence answer is 0.01



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3 years ago
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What is this number in standard form?
balandron [24]

Answer: y=5(x+15)2−26 5

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3 years ago
Giving brainlist to whoever answers
maxonik [38]

Answer: should be x> -18

Step-by-step explanation: hope this helps

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2 years ago
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the current temperature in small town - 20 degrees Fahrenheit this is 6 degrees less than twice the temperature that was six hou
Vlad [161]
For problems like this we can use algebra to help us, the farenheight 6 hours ago was:
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3 years ago
Find all real zeros of 4x^3-20x+16
Pani-rosa [81]

Answer:

  {1, (-1±√17)/2}

Step-by-step explanation:

There are formulas for the real and/or complex roots of a cubic, but they are so complicated that they are rarely used. Instead, various other strategies are employed. My favorite is the simplest--let a graphing calculator show you the zeros.

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Descartes observed that the sign changes in the coefficients can tell you the number of real roots. This expression has two sign changes (+-+), so has 0 or 2 positive real roots. If the odd-degree terms have their signs changed, there is only one sign change (-++), so one negative real root.

It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.

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Using synthetic division (or polynomial long division) to factor out x-1 (after removing the common factor of 4), we find the remaining quadratic factor to be x²+x-4.

The zeros of this quadratic factor can be found using the quadratic formula:

  a=1, b=1, c=-4

  x = (-b±√(b²-4ac))/(2a) = (-1±√1+16)/2

  x = (-1 ±√17)2

The zeros are 1 and (-1±√17)/2.

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The graph shows the zeros of the expression. It also shows the quadratic after dividing out the factor (x-1). The vertex of that quadratic can be used to find the remaining solutions exactly: -0.5 ± √4.25.

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The given expression factors as ...

  4(x -1)(x² +x -4)

5 0
3 years ago
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