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Veronika [31]
3 years ago
13

Write a function rule that gives the total cost c(p) of p pounds of sugar if each pound costs $.59. A. c(p) = 59p B. c(p) = p/0.

59 . C. c(p) = p + 0.59 D. c(p) = 0.59p
Mathematics
1 answer:
tia_tia [17]3 years ago
5 0
Your answer would be D because you are multiplying $0.59 by the number of pounds there are.
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ANSWER: y=7 is the equation Of the line that passes to through the point (-2,7) and Has a slope of zero.
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5. A video store charges a monthly
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Answer: 8 movies

12 + 1.50x = 3x

Move the variables to one side

12 = 1.50x

Isolate x

8 = x


Check:

3(8)= 24

12.00 + 1.50(8) = 24
8 0
3 years ago
2. The hundredths model is shaded to represent a division
solniwko [45]

Answer:

Option D

Step-by-step explanation:

If the whole grid is considered to be 1,

Each small grid will value = \frac{1}{100}=0.01

There are 72 shaded grids which represent the hundreds = 0.72

When these grids have been divided into 9 equal rows, number of grids in each row = 8

And the value of 8 grids in each row = 0.01 × 8 = 0.08

So the equation is,

0.72 ÷ 9 = 0.08

Therefore, equation represented by the model will be Option (D).

4 0
3 years ago
If you have 6.00 and apples selling for 88 cents a pound. How many apples can you buy?
Yuri [45]
6.81818181818 pounds of apples
3 0
3 years ago
Read 2 more answers
Which equation is true? I. (32 ÷ 8 – 2)6 = (32 – 1)2 II. 72 ÷ 9·4 = 62 ÷ (6 + 3) II only Neither I nor II I only I and II
Umnica [9.8K]

Answer: The answer is (b) Neither I nor II.


Step-by-step explanation: We are given two equations and we need to find which is true. Since it is a simple algebraic question, so we just need to follow BODMAS rule to check the equations.

The equations are as follows -  

(I)~~L.H.S=(\dfrac{32}{8}-2)6=(4-2)6=2\times 6=12.

R.H.S=(32-1)2=31\times 2=62.

Since L.H.S ≠ R.H.S, so this equation is not correct.

(II)~~L.H.S=\dfrac{72}{9\times 4}=2.

R.H.S=\dfrac{62}{6+3}=\dfrac{62}{9}.

Since L.H.S ≠ R.H.S, so this equation is also not correct.

Thus, the correct option is (b) Neither I nor II.


4 0
3 years ago
Read 2 more answers
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