Answer:
27 = 3 , 3, 3
63= 3 , 3, 7
54= 3 , 3, 3, 2
HCF OF 27, 63 AND 54 = 3 X 3 = 9
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We are asked to solve for the measurement of side BC in the given right triangle ΔABC and other side measurements were also given such as AB=1 and AC = 2. Since this is a right triangle, we can use and apply the Pythagorean theorem c²= a² + b² and the solution is shown below:
c = AC
b = BC
a = AB
AC² = AB² + BC² , substitute values we have:
2² = 1² + BC²
BC² = 4-1
BC = √3
BC = 1.732
The answer for the length of BC is 1.732 units.
C = 5(F-32)/9 Multiply each side by 9
9C = 5(F-32) Distribute
9C = 5F - 160 Add 160 to each side
9C + 160 = 5F Divide each side by 5
9/5C + 32 = F
-4, because it is four units away from zero.
Answer:
I think it's C not sure tho sry if wrong
