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Molodets [167]
4 years ago
7

12x>9 (2x-3)-15 solve for x and show steps please.

Mathematics
2 answers:
monitta4 years ago
5 0
First step is to distribute 9 over 2x-3

12x>18x-27-15

Next is to subtract 18x from both sides of the equation

-6x>-27-15 

Next is to subtract 15 from -27

-6x>-42

Finally just divide -42/-6

x>7

x has to be greater than 7 to satisfy this equation
Verdich [7]4 years ago
4 0

12x > 9(2x-3)-15

distribute the 9

12x > 18x-27 -15

combine like terms on the right side

12x > 18x-42

subtract 18x from both sides

-6x > -42

divide both sides by -6

x = -42 / -6 = 7

x >7

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How to use order of operation in 20 divide by 4 multiply 5 = 1
I am Lyosha [343]
Use PEMDAS. 20/(4*5)=1
Multiplication before dividion
6 0
3 years ago
The formula can be used to work outthe cost, in riyals, of hiring a helmet inQatar for a number of days.Kasun wants to hire a bi
Margaret [11]

Answer:

The answer is below

Step-by-step explanation:

a) Cost of hiring the bicycle for 14 days is:

Cost = 65 * 14 days + 44 = 954 riyals

b) The number of days the bicycle is hired is to be the same as the number of days the bicycle is to be hired. Let us assume that the bicycle and helmet is to be hired for x days, hence:

Cost of bicycle = 65 * x + 14 = 65x + 44

Cost of helmet = 12.5 * x = 12.5x

Total cost = 65x + 44 + 12.5x = 77.5x + 44

Since 750 riyals is available, hence:

750 = 77.5x + 44

77.5x = 706

x = 9.11

Therefore the maximum number of days is 11. The total cost for 11 days is:

Total cost = 77.5(9) + 44 = 741.5 riyals

Money not spent = 750 riyals - 741.5 riyals = 8.5 riyals

6 0
3 years ago
Someone help me out please
uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\   (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4.

2 step (A): simplify to obtain the final radical term on one side of the equation.

-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2.

3 step (F): raise both sides of the equation to the power of 2 again.

(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2.

4 step (E): simplify to get a quadratic equation.

4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0.

5 step (D): use the quadratic formula to find the values of x.

D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}.

6 step (C): apply the zero product rule.

x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}.

Additional 7 step: check these solutions, substituting into the initial equation.

3 0
3 years ago
What does the following equal? Please help me!
Juli2301 [7.4K]

Answer:

the first answer

Step-by-step explanation:

1/8 of the absolute value is 1/8 positive

anything from the absolute value is positive because absolute value is the value of how far away the number is from zero.

3 0
3 years ago
Read 2 more answers
Please answer! Give explanation to and follow steps to question. Tysm!!
iVinArrow [24]

Answer:

It would cost about $2.38

8 0
3 years ago
Read 2 more answers
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