Answer:
The roots are real and unequal (3, -3)
Step-by-step explanation:
x²-9=0
ax²+bx+c=0
Comparing we get,
a= 1
b= 0
c = -9
Determinant: b²-4ac
= 0² - 4(1)(-9)
= 36>0
D > 0
Therefore, the equation has real and unequal roots.
Algebraic identity:
x² - a² = (x-a)(x+a)
Using this identity
x²-9 = (x+3)(x-3)
Roots are 3 and -3 which are real and not equal to each other
Hope this answer helps you ..
Answer:
3x + 2y = 17
2x + 5 y = 26
Step-by-step explanation:
3x + 2y = 17 }
2x + 5 y = 26}
x - 3y = - 9
x = -9 + 3y
=> 2 (-9+3y)+5y=26
-18+6y+5y=26
-18+11y=26
11y=26+18
11y=44
y= 4
3x + 8=17
3x = 17 - 8
3x = 9
x = 9 : 3
x = 3
Answer:
a=1
b=2
c=-8
y-intercept: (0, -8)
Line of symmetry calculation: x = -2/(2*1)
Line of symmetry: -1
Opens up because a > 0
Minimum
Vertex: (-1, -9)
Domain: -∞ < x < ∞ (no domain constraints)
Range: [-9, ∞]
Step-by-step explanation:
Factor the equation so...
(r^2-pr) and (p^2q-pqr)
Factor out (r^2-pr) = r(r-p)
Factor out (p^2q-pqr) = pq(p-r)
Add a negative to r(r-p) to make it -r(p-r)
(pq-r)(p-r) is the answer... I'm sorry I can't explain things well, but I tried.
1) Correct.
2) The y-intercept is when x=0, so it is (0,5).
