25/64 is the answer to your question
Answer:
y = 0.265x - 494.7
Step-by-step explanation:
Let median age be represent by 'a' and time be represent by 't'
In 1980, median age is given 30
which means that
a₁ = 30
t₁ = 1980
In 2000, the median age is given 35.3
which means that.
a₂ = 35.3
t₂ = 2000
The slope 'm' of the linear equation can be found by:
m = (a₂ - a₁) /(t₂ - t₁)
m = (35.3 - 30)/(2000-1980)
m = 0.265
General form of linear equation is given by:
y = mx + c
y = 0.265x +c
Substitute point (1980,30) in the equation.
30 = 0.265(1980) + c
c = -494.7
Hence the the linear equation can be written as:
y = mx + c
y = 0.265x - 494.7
Answer:
y=-5/3x+20
Step-by-step explanation:
Let the equation of the required line be represented as ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
This line is perpendicular to the line ![\[y=\frac{3}{5}x+10\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B3%7D%7B5%7Dx%2B10%5C%5D)
![\[=>m*\frac{3}{5}=-1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%2A%5Cfrac%7B3%7D%7B5%7D%3D-1%5C%5D)
![\[=>m=\frac{-5}{3}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%3D%5Cfrac%7B-5%7D%7B3%7D%5C%5D)
So the equation of the required line becomes ![\[y=\frac{-5}{3}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2Bc%5C%5D)
This line passes through the point (15.-5)
![\[-5=\frac{-5}{3}*15+c\]](https://tex.z-dn.net/?f=%5C%5B-5%3D%5Cfrac%7B-5%7D%7B3%7D%2A15%2Bc%5C%5D)
![\[=>c=20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ec%3D20%5C%5D)
So the equation of the required line is ![\[y=\frac{-5}{3}x+20\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2B20%5C%5D)
Among the given options, option 4 is the correct one.
1/2 of 22:
1/2 · 22 = 22/2 = 11
2/3 of 16
2/3 · 16 = 32/3 = 10 2/3
I would go with B but this is a tricky question. Hopefully i am correct.