Answer:
A.
Step-by-step explanation:
Both equations are solved for y so I'm just going to substitute
the 1st y (the 2x+4) into the second equation's y.
I'm going to get everything on one side so I have 0=ax^2+bx+c.
Subtract 2x and subtract 4 on both sides:
Since the coefficient of x^2 is 1, all we have to do is find two numbers that multiply to be -6 and add up to be -1.
These numbers are -3 and 2.
So the factored form of our equation is:
This means we have x-3=0 or x+2=0.
x-3=0
Add 3 on both sides:
x=3
x+2=0
Subtract 2 on both sides:
x=-2
So now we need to find y. I'm going to choose to use the easier equation:
y=2x+4.
If x=3, then y=2(3)+4=6+4=10. The ordered pair (3,10) is a solution.
If x=-2, then y=2(-2)+4=-4+4=0. The orded pair (-2,0) is a solution.