Recall your d = rt, distance = rate * time
one car is going at 55kph, at say hmmm "t" time
the second car zooms by at 75kph, an hour later, thus " t + 1 "
notice, overtaking the 1st car, simply means, the second car comes from behind approaches the first car from behind and "gets there", at that very second, both cars have travelled a distance, say "d"
if the first car travelled "d" kilometers
for the second car to "get there" has to had travelled "d" distance as well
solve for "t"
Translate 5 units to the right, and 2 units down
Glenda is incorrect. shes wrong because she wrote 4/10 thats close to 1/2 but its not one half
The required solution is ∠RQT = 202° and ∠QTS = 51°
<h3 />
<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
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Not really sure what you are looking for, but this is how to solve equations such as these.
Let:
x = number of pounds of granola
y = numer of pounds of walnuts
The equation he can use to compute the total cost would be:
$2.00x + $6.00y = $12.00
We know that he bought 3 pounds of granola, so we plug in that for the x value:
$2.00(3) + $6.00y = $12.00
$6.00 + $6.00y = $12.00
To isolate the unknown value which is y, we first need to subtract $6.00 from both sides of the equation:
$6.00 + $6.00y - $6.00 = $12.00 - $6.00
$6.00y = $6.00
Then we divide both sides by $6.00:
$6.00y/$6.00 = $6.00/$6.00
y = 1
So the number of bags of walnuts he can buy is 1 bag.
