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qaws [65]
3 years ago
11

For her phone service, Rita pays a monthly fee of $17, and she pays an additional $0.05 per minute of use. The least she has bee

n charged in a month is $83.90.
What are the possible numbers of minutes she has used her phone in a month?

Use M for the number of minutes, and solve your inequality for M.​
Mathematics
1 answer:
Alona [7]3 years ago
3 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Monthly fee = $17

Additional fee per unit of use = $0.05

Least amount she's been charged in a month = $83.90

Equation to represent the number of minutes 'M':

monthly fee + (additional fee per minute × M) = $83.90

Possible number of minutes :

83.90 ≤ $17 + 0.05M

$17 + $0.05 × M = $83.90

$0.05*M = $83.90 - $17

$0.05*M = $66.90

M = $66.90 / 0.05

M = 1,338 minutes

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Answer:

<em>The amount of water in the reservoir at the beginning of second week</em>

<em></em>w_{2} = 299.8800<em></em>

Step-by-step explanation:

<u>Step(i):</u>-

<em>Given equation </em>

<em>   w₀ = 300  and </em>

w_{n} = (0.9993) w _{n-1} + 0.15

Put n =1

w_{1} = (0.9993) w _{1-1} + 0.15

w_{1} = (0.9993) w _{0} + 0.15

w_{1} = (0.9993) X 300 + 0.15

w_{1} = 299.94

<u><em>Step(ii)</em></u>:-

<em>Put n =2</em>

w_{2} = (0.9993) w _{2-1} + 0.15

w_{2} = (0.9993) w _{1} + 0.15

w_{2} = (0.9993) X (299.94) + 0.15

w_{2} = 299.8800

<u><em>Conclusion:</em></u>-

<em>The amount of water in the reservoir at the beginning of second week</em>

<em></em>w_{2} = 299.8800<em></em>

<em></em>

                     

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