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Anna007 [38]
2 years ago
12

"My car gets 30 miles per gallon when I drive on the highway and 25 miles per gallon when I drive in the city. How many highway

miles do I drive on a 400-mile trip if the car consumes 14 gallons of gasoline during this trip?"
Mathematics
1 answer:
8090 [49]2 years ago
5 0

Answer:

300 miles

Step-by-step explanation:

Let the gallons of fuel used on highway be X

gallons of fuel used in city  be Y

Given that total no of gallons consumed on trip is 14

hence

X + Y =  14  -----------------------equation A

__________________________________________

Given

no. of miles car can drive on highway using 1 gallon of fuel = 30

therefore

no. of miles car can drive on highway using X gallon of fuel = 30X

no. of miles car can drive in city using 1 gallon of fuel = 25

therefore

no. of miles car can drive in city  using Y gallon of fuel = 25Y

Given that total miles driven on trip is 400 miles

therefore

30X + 25 Y = 400   ---------------------------------equation B

_________________________________________________

now we have two equation

X + Y =  14  -----------------------equation A

Y = 14 - X   -----------------------equation C

30X + 25 Y = 400   ---------------------------------equation B

substituting value of Y from equation C in equation B we have

30X + 25 Y = 400

=> 30X + 25 (14 - X) = 400

=>30X + 350 - 25X = 400

=> 5X = 400 - 350 = 50

=> X = 50/5 = 10

Y = 14 - X = 14 - 10 = 4

________________________________________________________

now we have to find miles drove on highway

we have defined above

no. of miles car can drive on highway using X gallon of fuel = 30X

where X is no of gallons of fuel used on highway

therefore

no. of miles car can drive on highway using X gallon of fuel = 30*10 = 300

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A department​ store, on​ average, has daily sales of ​$28 comma 286.28. The standard deviation of sales is ​$1 comma 500. On​ Tu
wolverine [178]

Answer:

z-score = 4.43,

It is a Good day

Step-by-step explanation:

The provided information is:

Mean = $28,286.28

Standard deviation = $1,500

Let x be the sell of department store on Tuesday.

Then, x = $34,924.62

The z-score is define as:

z=\dfrac{x-\mu}{\sigma}\\\\=\dfrac{34924.62-28286.28}{1500}\\\\=4.43      

Thus, the Tuesday's z-score is 4.43. So this is usually good day.

3 0
3 years ago
A croissant shop produces two products: bear claws (B) and almond filled croissants (C). Each bear claw requires 6 oz of flour,
Kruka [31]

Answer:

letter A: B = 400; C = 1000; Max Z = $380

Step-by-step explanation:

bear claws (B) need 6 oz of flour (f), 1 oz of yeast (y), 2 ts of paste (p)

croissants (C) need 3 oz of flour (f), 1 oz of yeast (y), 4 ts of paste (p)

putting that information in equations, we have:

B = 6f + y + 2p

C = 3f + y + 4p

The total number of resources (R) are:

R = 6600f + 1400y + 4800p

Let's call M our total profit, "k1" the number of B produced and "k2" the number of C produced.

So, we can state that:

M = k1*0.2 + k2*0.3

The number of resources R2 will demand is calculated like this:

R2 = k1*B + k2*C = (6k1+3k2)f + (k1+k2)y + (2k1+4k2)p

using R2 and R, we can make some inequations:

6k1+3k2 <= 6600 -> 2k1+k2 <= 2200

k1+k2 <= 1400

2k1+4k2 <= 4800 -> k1+2k2 <= 2400

if we try to maximize k2 (as it worths more), we will have k1 = 0 and k2 = 1200 (limited by p), but looking at the resources R, we will still have resources to use (f and y). Looking at B and C expressions, we see that removing one C gives enough 'p' to make 2 B, which is a good trade (as 2B worths 0.4 cents, and 1C worths 0.3 cents). we have 200 'y' remaining, so doing this 200 times give us k1 = 400 and k2 = 1000, and the only resource remaining will be some of 'f'.

calculating the profit M, we have:

M = 400*0.2 + 1000*0.3 = 380$

the right answer is letter A.

3 0
3 years ago
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