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Misha Larkins [42]
3 years ago
11

Abby is constructing the inscribed circle for △JKL .

Mathematics
2 answers:
Nady [450]3 years ago
5 0
Just took quiz. Correct answer is B
alex41 [277]3 years ago
3 0

Answer:

Hence, the correct answer is:

<em>Construct the angle bisector of ∠J .</em>

Step-by-step explanation:

The steps for the construction of inscribed circle are:

  • Bisect one of the angles
  • Bisect another angle
  • Where they cross is the center of the inscribed circle, called the incenter
  • Construct a perpendicular from the center point to one side of the triangle
  • Place compass on the center point, adjust its length to where the perpendicular crosses the triangle, and draw your inscribed circle!.

The answer that best suits the construction among the given option is:

Construct the angle bisector of ∠J.

(Since first steps of the construction will be satisfied)

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6 0
2 years ago
What is LaTeX: m\angle PQRm ∠ P Q R? Line PS with midpoint at Q and ray QR. Angle pqr is 3x-6 and angle rqs is x+2
Mkey [24]

Answer:

<h3>132°</h3>

Step-by-step explanation:

If line PS has midpoint a Q and ray QR, then line PQS will be a straight line and <PQR + <RQS = 180 (sum of angle on a straight line).

Given

<PQR = 3x-6

<RQS = x+ 2

To get x, we will use the relationship above;

3x-6+x+2 = 180

4x-4 = 180

add 4 to both sides

4x-4+4 = 180+4

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x = 184/4

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Since <PQR = 3x-6, we will substitute the value of x into the formula;

<PQR = 3x-6  

<PQR = 3(46)-6

<PQR = 138-6

<PQR = 132°

Hence the size of angle PQR is 132°

6 0
3 years ago
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