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STALIN [3.7K]
3 years ago
6

Help ASAP please ! Explain too for brainlist

Mathematics
1 answer:
musickatia [10]3 years ago
7 0

Answer:

Ok so im not the best at explaining but its worth a shot

C)25

Step-by-step explanation:

we already know that the formula to find area is

A=l*w

and that every square is 1 square unit.

So in the first part on the far left, you count down 8 and over 2 to find how many total squares are shaded. This is the length and width of that one part  so you multiply 8*2 to get 16.

In the next part, you should count starting at -1 over to 5 to get 6. It only has a width of 1 so 6*1 is still 6.

In the last part you start counting at -3 and count down to -6 and this gives you 3. It is 1 unit wide so 3*1 is 3.

Add 16+6+3 together because that is the combined area of the 3 parts and we get 25

Like i said im definitely, by no means, the best at explaining but if this helped even a little that's awesome, if you have any particular questions i can try to answer them in the comments

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(0-0)÷(-3-5)=0
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Answer:

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When we talk about division, a number 'A' is divisible by any other number 'B',

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So, As per the question, we have to check whether numberOfPrizes is divisible by numberOfParticipants, the expression is

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3 years ago
Find the mass of the solid paraboloid Dequals=​{(r,thetaθ​,z): 0less than or equals≤zless than or equals≤8181minus−r2​, 0less th
Lubov Fominskaja [6]

Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

                             0 ≤ z ≤ 81 - r^2

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Find the mass of the solid paraboloid

Solution:-

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                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

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                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

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Hello

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