3 years ago

How many solutions does the system of equations have?

Mathematics

2 answers:

torisob [31]3 years ago

8 0

Answer is =c due to the one solution

Vlad1618 [11]3 years ago

4 0

Answer:

one solution at x=1,y=4 point

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Lelechka [254]

1) Solving $4a+4b-ac-bc$ we get $(a+b)(4-c)$

2) Solving $16a^4-8b$ we get $8(2a^4-b)$

3) Solving $x^2-8x+15$ we get $(x-3)(x-5)$

Step-by-step explanation:

We need to solve the following expressions:

1) $4a+4b-ac-bc$

We will solve this expression by factoring common terms:

$4a+4b-ac-bc$

Factoring 4 from 4a+4b and -c from -ac-bc

$4(a+b)-c(a+b)$

Taking common term

$(a+b)(4-c)$

2) $16a^4-8b$

We will solve this expression by factoring common terms:

$16a^4-8b$

Taking 8 as common term:

$8(2a^4-b)$

3) $x^2-8x+15$

We can solve the expression by breaking the middle term into 2

$x^2-3x-5x+15\\Finding\,\,common:\\=x(x-3)-5(x-3)\\=(x-3)(x-5)$

Keywords: Finding factors

Learn more about Finding factors at:

#learnwithBrainly

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