In this question, the first information that we get is that Kayla spent half of her weekly allowance in clothes. On cleaning the oven Kayla gets $4. Finally Kayla is left with $12.
Let us assume that the weekly allowance of Kayla = x
Amount of allowance saved after buying clothes = x/2
Then we can go for the equation
x/2 + 4 = 12
x + (4 * 2) = 12 * 2
x + 8 = 24
x = 24 -8
= 16
So we can now see that the weekly allowance of Kayla is $16

5 0

3 years ago

a container holds 15 pennies 8 nickels and 10 dimes you will randomly select two coins without replacement what is the probabili

AlexFokin [52]

<span>A container holds 15 pennies, 8 nickels, and 10 dimes.
You will randomly select two coins without replacement.
-->Fill in the probabilities on a tree diagram.</span>

3 0

3 years ago

Which expression represents 43 minus the sum of 16 and 11

gogolik [260]

Answer:

43-(16*11) = -133

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officia

Svetradugi [14.3K]

Answer:

2630 g

Step-by-step explanation:

From the given information:

Given that:

mean (μ) = 3750 g

Standard deviation (σ) = 500

Suppose the hospital officials demand special treatment with a percentage of lightest 3% (0.03) for newborn babies;

Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;

P(Z < z₁) = 0.03

Using the Excel Formula; =NORMSINV(0.03) = -1.88

z₁ = - 1.88

Using the test statistics z₁ formula:

$z_1 = \dfrac{X-\mu}{\sigma}$

$-1.88 = \dfrac{X-3570}{500}$

By cross multiply, we have:

-1.88 × 500 = X - 3570

-940 = X - 3570

-X = -3570 + 940

-X = -2630

X = 2630 g

Hence, 2630 g is the required weight of birth that differentiates the babies that needed special treatment from those that do not

6 0

2 years ago