Question:
At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank
Answer:
The percent Decrease of water in the tank is 50%
Step-by-step explanation:
Given:
Initial amount of water in the tank at the noon = 6 cm
amount of water remained in water after several hours = 3 cm
To Find:
The percent decrease =?
Solution:
The percent decrease in the tank
=>
Substituting the values
=>
=>
=>
=> 50
The answer will be 2.
46 / 23 is 2.
http://coolconversion.com/math/fractions-simplifier/Reduce__46/23_to%20the%20simplest%20form
This proves my answer.
Answer:
Here is your answers. Make it as brainliest answer so I can help you in future assignments.
Answer:
143 because if you subtract 49 and 28 you get 21 the you divide 21 and 1623
Answer: Okay so do 3x7.5 then 3x11.5 then 7.5x11.5 then add it up and you should get 143.25