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Elza [17]
3 years ago
12

What is the constant of variation for the quadratic variation? x=2,3,4,5,6 y= 32,72,128,200,288

Mathematics
1 answer:
Bad White [126]3 years ago
7 0
Hello,
y=a*x² ==>
32=a*2²==>a=32/4=8
72=a*3²==>a=72/9=8
128=a*4²==>a=128/16=8
200=a*5²==>a=200/25=8
288=a*6²==>a=288/36=8

Answer A: 8

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Note: The quantities described are as follows:

1) the allowable number of players on a team  

2) the number of points,  , Han's team earns in one round if every player earns a perfect score  

3) the number of points,  , Han's team earns in one round if no players earn a perfect score  

4) the number of players,  , in a game with six teams of different sizes: two teams have 4 players each and the rest have 3 players each

5) the possible number of players in a game with eight teams

Step-by-step explanation:

1. Let the number of players be n

Since each team can have between 2 and 4 players

n ≥ 2 or 2 ≤ n, and n ≤ 2

Therefore, the allowable number of players on a team   is given by 2 ≤ n ≤ 4

2) There are four players in Han's team and a perfect score is 20

Therefore, the number of points Han's team earns in one round if every player earns a perfect score   is given by 4 * 20

3) There are four players in Han's team

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Let the total score of Han's team be T

Therefore, the number of points, Han's team earns in one round if no players earn a perfect score   is given by T < 80

4) If two team have 4 players, it is given by 2 * 4

If the rest four teams have 3 players each, it is given by 4 * 3

Therefore, the number of players in a game with six teams of different sizes: two teams have 4 players each and the rest have 3 players each  is given by (2 * 4) + (4 * 3)

5) Let the possible number of players in a game with be P

Maximum number of players in eight teams = 4 * 8 = 32

Minimum number of players in eight teams = 2 * 8 = 16

P ≤ 32 and P ≥ 16 or 16 ≤P

Therefore, the possible number of players in a game with eight teams  is given by 16 ≤ P ≤ 32

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3 years ago
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