Positive and a positive, will always be a positive because theyre both the same. If two things are the same, theyre equal. ( this is from what ik,I read it as a common sense question)
Answer:
eu nao sei, mas preciso de pontos kkdescukpe okay
<h3>
Answer: x-2</h3>
Explanation:
If x > 2, then x-2 > 0 after subtracting 2 from both sides.
Since x-2 is always positive when x > 2, this means the absolute value bars around the x-2 aren't needed. The results of |x-2| and x-2 are perfectly identical.
For example, if we tried something like x = 5, then
- x-2 = 5-2 = 3
- |x-2| = |5-2| = |3| = 3
Both outcomes are 3. I'll let you try other x inputs.
So because |x-2| and x-2 are identical, this means |x-2| = x-2 for all x > 2.
In short, we just erase the absolute value bars.
Answer : p=2
2p-2-5x=-2(7-2x)
First, work on the parentheses. So the -2 on the outside as to be multiplied by the 7 , which gets -14 . Then you multiply the -2 by the 2x, which is 4x.
It will go from -2(7-2x) to -14+4x
But if the -14+4x looks too confusing, you can just switch them around to look “normal”. So it would be 4x-14 .
Now that we’re finished with one side of the problem, we’ll go to the other side.
On the left side , there are two variables, or letters. Because they are the same letter (p) all you have to do is add them together.
3p
-5p
+—-
-2p
And then just carry the -2 that was originally there , so it’s -2p-2
Now the equation is
-2p-2 = 4p-14
So we’re going to add 2p to both sides.
The -2p on the left cancels out, and the 4p on the right side becomes 6p
-2 = 6p-14
Next, you are going to want to isolate the variable. (Leave the letter by itself) so you add 14 to the -14 , so it can cancel out. (AND DO THE SAME ON THE OTHER SIDE)
So, you add 14 to the -2 on the left of the equation. Which comes out to 12.
12 = 6p
Lastly, divide the 6p , so you can get the letter on it’s own. And do the same on the other side.
12 divided by 6 is 2
2 = p
OR
p = 2
