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kolbaska11 [484]
3 years ago
11

Why is the actual dihedral angle of gauche butane different from 60degrees?

Chemistry
1 answer:
tatyana61 [14]3 years ago
5 0

Answer:The actual dihedral angle of gauche butane differs because of a phenomenon known as steric effect.

Explanation: Steric effect is phenomenon that influences the shape and reactivity of ions and molecules caused by nonbonding interactions.

Steric effects goes with electronic effects, which usually tells the shape and reactivity.

Steric effects is a result of repulsive forces between overlapping electron clouds activities. These steric effects will even distort angles and molecular geometries.

In the context of butane, because presence of two bulky methyl groups (-CH3), the steric interference occurs which causes the methyl groups to be some what far apart hence, increasing the dihedral angle between the two methyl groups which in turn, affects the dihedral angles of other groups present in the molecules.

Therefore, the dihedral angles between the hydrogens are not exactly 60 or 180 degrees.

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Explanation:

the volume and temperature of a gas have a ditect relationship,as the temperature increases the volume also increases when pressure is held constand, heating the gas increases the kinetic energy of the particles or atoms,causing the gas to expand until the pressure returns to its original value

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The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s
raketka [301]

Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

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                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

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The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

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3 years ago
A 5.00 L sample of helium expands to 12.0 L at which point the
mina [271]

Answer:

1.73 atm

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Initial volume of helium = 5.00 L

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Final pressure = 0.720 atm

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P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

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P₁V₁ = P₂V₂

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