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loris [4]
3 years ago
5

The half-life of a pesticide determines its persistence in the environment. A common pesticide degrades in a first-order process

with a rate constant of 6.5 1/hours. What is the half-life in hours of the breakdown reaction? Enter to 4 decimal places.
Chemistry
1 answer:
denis23 [38]3 years ago
7 0

Answer:

0.1066 hours

Explanation:

A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.

t1/2 = ln2/k

t1/2 = ln2/6.5 h⁻¹

t1/2 = 0.1066 h

The half-life of the pesticide is 0.1066 hours.

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134 grams of nitric acid is added to 512 grams of water. Calculate the molality of nitric acid.
Nana76 [90]

Answer:   4.15234 m

512 g H2O * \frac{1 kg}{1000 g} = 0.512 kg H2O

Nitric Acid:  HNO3 = 1.008 + 14.007 + 3(15.999) = 63.012 g/mol

H = 1.008 g/mol

N = 14.007 g/mol

O3 = 3*15.999

134 g HNO₃ * \frac{mol}{63.012 g} = 2.126 mol

m = \frac{2.126  mol}{0.512  kg} = 4.15234 m

6 0
3 years ago
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is the approximate relation celsius = 1/2 fahrenheit a better approximation at higher or lower temperatures?
kirill115 [55]

Answer : The approximate relation Celsius = 1/2 Fahrenheit is a better approximation at higher temperatures

Explanation :

The formula for Celsius to Fahrenheit conversion is

C = (F-32) \times \frac{5}{9}

At lower temperature the value that needs to be subtracted (32) is large enough as a result the approximation "celsius = 1/2 fahrenheit " does not seem valid.

For example, 50 F is 10°C.

(50 - 32) \times \frac{5}{9} = 10 C

This is almost 1/5 of Fahrenheit temperature.

But at higher temperatures , the value becomes insignificant and also the ratio  5/9 tend to be equal to 0.5.

For example, 2000 F is 1093°C

(2000 - 32) \times \frac{5}{9} = 1093 C

This is almost half of Fahrenheit temperature.

Therefore , the approximate relation Celsius = 1/2 Fahrenheit is a better approximation at higher temperatures

8 0
3 years ago
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natta225 [31]

Explanation:

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300N x 1m

workdone= 300J

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