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gulaghasi [49]
3 years ago
6

What are the 6 elements of wether

Chemistry
1 answer:
Citrus2011 [14]3 years ago
8 0
The six basic elements of weather include temperature, humidity, atmospheric pressure, wind, precipitation, and cloudiness.

~I knew this was asked 5 days ago, but I hope this still helps.








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Calculate the mass, in grams, of 122 atoms of iron, Fe (1 mol of Fe has a mass of 55.85 g).
vitfil [10]

Answer:

6813.7g

Explanation:

Calculate the mass

Let x be the mass

If 1 mol of Fe has a mass of 55.85 g

1 mol =55.85g

122mol= x

we have x= 122•55.85g=6813.7g

7 0
3 years ago
What is programming language? Describe it's types.<br>​
umka21 [38]
A programming language is a vocabulary and set of grammatical rules for instructing a computer device to perform specific tasks. the term programming language usually refers to high level languages, such as BASIC, C, C++, COBOL, Java, FORTRAN, Ada, and Pascal! i hope i was able to help :)
7 0
3 years ago
When the following equation is balanced, what is the coefficient for HBr?
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D.) Balanced equation is Zn + 2HBr - - - > ZnBr2 + H2.
4 0
4 years ago
Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your
k0ka [10]
We cannot solve this problem without using empirical data. These reactions have already been experimented by scientists. The standard Gibb's free energy, ΔG°, (occurring in standard temperature of 298 Kelvin) are already reported in various literature. These are the known ΔG° for the appropriate reactions.

<span>glucose-1-phosphate⟶glucose-6-phosphate          ΔG∘=−7.28 kJ/mol
fructose-6-phosphate⟶glucose-6-phosphate          ΔG∘=−1.67 kJ/mol
</span>
Therefore, the reaction is a two-step process wherein glucose-6-phosphate is the intermediate product.

glucose-1-phosphate⟶glucose-6-phosphate⟶fructose-6-phosphate 

In this case, you simply add the ΔG°. However, since we need the reverse of the second reaction to end up with the terminal product, fructose-6-phosphate, you'll have to take the opposite sign of ΔG°.

ΔG°,total = −7.28 kJ/mol  + 1.67 kJ/mol = -5.61 kJ/mol

Then, the equation to relate ΔG° to the equilibrium constant K is

ΔG° = -RTlnK, where R is the gas constant equal to 0.008317 kJ/mol-K.
-5.61 kJ./mol = -(0.008317 kJ/mol-K)(298 K)(lnK)
lnK = 2.2635
K = e^2.2635
K = 9.62


6 0
3 years ago
Read 2 more answers
What is the molecular mass of Br 2?
Kazeer [188]

Answer:

159.808 g/mol

3 0
3 years ago
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