Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:

item i:
Velocity is the <u>derivative of the position</u>, hence:

Item ii:

The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:

Item iv:

The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:




Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
The answer is 51/40=1 and 11/40
Answer:
1 5/7
Step-by-step explanation:
-9 2/7 -(-10 3/7) recall -×- = +
-9 2/7 +10 3/7
1 2+3/7
1 5/7
Answer:
9/10 I do this a lot
step-by-step explanation:
1/2 changes to 5/10 and 2/5 becomes 4/10 then you add and there is your answer
Answer:
565.49 or if rounded to the nearest tenth, 565.5
Explanation:
The formula for finding the volume of a cone is V=1/3Bh
B = pi times the radius squared
h = height
Substitute 6 for r and 15 for h.
V= 1/3·
·(
)·15
Multiply.
V= 565.49 or 565.5 rounded to the nearest tenth.