(x-1)(x+1)(x-3)(x+3)
x²-y² formula
Mark brainliest please
Hey there! :D
When powers are outside the parenthesis, you multiply them. When they are not, you add them.
(y^3)^2 * y^7
3*2= 6
y^6*y^7
Add the powers.
y^13= the simplest form
I hope this helps!
~kaikers
Answer:
1/2
Step-by-step explanation:
Since the recessive gene is carried in the x chromosome and a father can only pass it to a daughter, the father doesn't have the disease nor carries it.
The mother carries the recessive gene because her father passed her his conditioned gene (only having one x chromosome), while her mother gave her a normal one so she can have normal vision.
The chance of having a boy or a girl is 1/2 and the chance of this baby of having both recessive gene is null because in order to have a girl that is color blind both her x chromosomes must have the recessive gene, but the father can't pass it since he doesn't carries it. Therefore the combined probability is 1/2*(1-0) = 1/2.
6n - 13 = 27
6n = 27 + 13
6n = 40
n = 40/6
n = 6 2/3
Answer: n = 6 2/3
(n-4)(n+11) so pretty much B
