Answer:
The first car was traveling 70 mph, while the second was driving 50 mph.
Step-by-step explanation:
Set the cars as a proportion:

X represents the speed of the second car. By cross multiplying, you get the following equation:

You solve by distributing 150 to get 210x = 150x + 3000.
Solving for x gets you 50.
That means the first car was going at 50 mph. Adding 20, you get 70 as the speed for the second car.
Answer:
Let the side of one square be x. Area = x*x = x²
Then the side of other square would be 2x , Area = 2x*2x = 4x²
Combined area = x² + 4x² = 5x²
This combined area = 45 cm²
you simplify
Therefore 5x² = 45 Divide both sides by 5
x² = 45/5
x² = 9 Take square root of both sides
x = √9
x = 3
Length of larger square is 2x = 2*3 = 6 cm
Length of larger square = 6cm
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
Answer:
11 is one of the factors! The orange divisor(s) above are the prime factors of the number 990. If we put all of it together we have the factors 2 x 3 x 3 x 5 x 11 = 990.
Step-by-step explanation:
Answer:
The weight of the block of ice after 1 day is of 4.81 pounds.
Step-by-step explanation:
Equation for exponential decay:
The equation that models an amount after t hours, subject to exponential decay, is given by:

In which A(0) is the initial amount and r is the decay rate, as a decimal.
A 10-pound block of ice melts at a rate of 3% per hour.
This means that 
So



Find the weight of the block of ice after 1 day.
One day has 24 hours, so this is A(24).

The weight of the block of ice after 1 day is of 4.81 pounds.