Answer:
So estimate.
Really depends on what needs to be estimated, the answer or the overall equation.
So doing the real one first.
283/11 = 25 8/11
You can’t have “part” of a student so rounding this you can go up since 8 is more then half of 11
So 26 students
If you were to round the overall equation then you’d get
280 / 10 which is 28 students per class
So two options.
Answer:
x ≈ -4.419
Step-by-step explanation:
Separate the constants from the exponentials and write the two exponentials as one. (This puts x in one place.) Then use logarithms.
0 = 2^(x-1) -3^(x+1)
3^(x+1) = 2^(x-1) . . . . . add 3^(x+1)
3×3^x = (1/2)2^x . . . . .factor out the constants
(3/2)^x = (1/2)/3 . . . . . divide by 3×2^x
Take the log:
x·log(3/2) = log(1/6)
x = log(1/6)/log(3/2) . . . . . divide by the coefficient of x
x ≈ -4.419
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A graphing calculator is another tool that can be used to solve this. I find it the quickest and easiest.
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<em>Comment on alternate solution</em>
Once you get the exponential terms on opposite sides of the equal sign, you can take logs at that point, if you like. Then solve the resulting linear equation for x.
(x+1)log(3) = (x-1)log(2)
x=(log(2)+log(3))/(log(2)-log(3))
Answer:Just solve it. This is Algebra. Not that hard. Use Substation Method
Step-by-step explanation:
Answer:
No, (8,5) is not a solution of y > x + 7
Step-by-step explanation:
Hope you got it.
Answer: 820,000
823,563 rounded to the nearest ten thousand is 820,000