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3 years ago

Find the measure of the angle indicated in bold Plss help

Mathematics

2 answers:

MAXImum [283]3 years ago

8 0

Answer:

Solution given:

9x-4=8+7x[Vertically opposite angle]

9x-7x=8+4

2x=12

x=12/2

x=6

:.8+7x=8+7×6=50°

Hitman42 [59]3 years ago

6 0

Answer:

Step-by-step explanation:

9x - 4 = 8 + 7x

x = 6

Therefore, 8 + (7 *6) = 50

The measure of the angle is 50

Thenks and mark me brainliest :)))

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Solve for t 64= -8(t+85)

erastova [34]

Answer: t = -93

Step-by-step explanation:

64= -8(t+85)

64= -8t - 680

744= -8t

93= -t

93= t

4 0

2 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

3 years ago

Term

abruzzese [7]

The computer regression output includes the R-squared values, and adjusted R-squared values as well as other important values

a) The equation of the least-squares regression line is $\underline {\hat y = 235 \cdot x + 10835}$

b) The correlation coefficient for the sample is approximately 0.351

c) The slope gives the increase in the attendance per increase in wins

Reasons:

a) From the computer regression output, we have;

The y-intercept and the slope are given in the Coef column

The y-intercept = 10835

The slope = 235

The equation of the least-squares regression line is therefore

$\underline {\hat y = 235 \cdot x + 10835}$

b) The square of the correlation coefficient, is given in the table as R-sq = 12.29% = 0.1229

Therefore, the correlation coefficient, r = √(0.1229) ≈ 0.351

The correlation coefficient for the sample, r ≈ 0.351

c) The slope of the least squares regression line indicates that as the number of attending increases by 235 for each increase in wins

Learn more here:

brainly.com/question/2456202

8 0

2 years ago

The common difference ,d in an arithmetic sequence whose fourth term is 16 and whose seventh therm is 31

Natali [406]

Answer: d=5

Step-by-step explanation:

Arithmetic progression

An=a1+d(n-1)

An= nth term

A1= first term

D= common difference

N= nth position

We are given the 4th and 7th terms

For 4th term,n=4

A4=a1+d(4-1)

A4= 16

16= a1+d(4-1)

16= a1+3d........equation 1

For the 7th term,n=7

A7=a1+d(7-1)

A7= 31

31=a1+6d......equation 2

Bring them together

16=a1+3d

31=a1+6d

Subtract equation 1 from 2

So we have

15=3d

D=15/3

D=5

Therefore, the common difference is 5

3 0

3 years ago

The mathematical model C (x) = 200x + 10,000 represents the cost in dollars a company incurs when

Reil [10]

We have been given a function $C(x)=200x+10,000$ represents the cost in dollars a company incurs when producing x items during a month. We are asked to find the cost to produce 50 items.

To find the cost to produce 50 items, we will substitute $x=50$ in our given function as:

$C(50)=200(50)+10,000$

$C(50)=10,000+10,000$

$C(50)=20,000$

Therefore, it will cost $20,000 to produce 50 items.

5 0

3 years ago